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HELP ASAPPPP PLEASE ! please do them ALL

Posted: Thu Jul 07, 2022 12:10 pm
by answerhappygod
HELP ASAPPPP PLEASE !
please do them ALL
Help Asapppp Please Please Do Them All 1
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How many grams of benzoic acid, C6H5COOH, must be dissolved in 45.4 g benzene, C6H6, to produce 0.191 m C6H5COOH? Be sure to enter a unit with your answer. Answer: A gas mixture contains 0.167 mol nitrogen, 0.386 mol oxygen and 0.529 mol argon. Calculate the mole fraction of argon in the mixture. Answer:
How many grams of benzoic acid, C6H5COOH, must be dissolved in 45.4 g benzene, C6H6, to produce 0.191 m C6H5COOH? Be sure to enter a unit with your answer. Answer: A gas mixture contains 0.167 mol nitrogen, 0.386 mol oxygen and 0.529 mol argon. Calculate the mole fraction of argon in the mixture. Answer:
Calculate the mass (in grams) needed to prepare 872 mL of a 5.08 M NH4Cl solution. You do not need to enter units with your answer. Answer: A gas mixture contains 49.4 g of carbon monoxide, CO, and 565 g of carbon dioxide, CO₂. What is the mole fraction of carbon monoxide? Answer:
Calculate the mass (in grams) needed to prepare 872 mL of a 5.08 M NH4Cl solution. You do not need to enter units with your answer. Answer: A gas mixture contains 49.4 g of carbon monoxide, CO, and 565 g of carbon dioxide, CO₂. What is the mole fraction of carbon monoxide? Answer:
How many grams of benzoic acid, C6H5COOH, must be dissolved in 45.4 g benzene, C6H6, to produce 0.191 m C6H5COOH? Be sure to enter a unit with your answer. Answer: A gas mixture contains 0.167 mol nitrogen, 0.386 mol oxygen and 0.529 mol argon. Calculate the mole fraction of argon in the mixture. Answer: