Answer Happy

A 15 tum circular loop of wire is placed into a magnetic field with initial magnitude 3.9 1. The magnetic field is perpendicular to the surface of the loop Over a period of 0 36 seconds, the strength of the field is decreased to 1.3 T and as the field decreases a 3.5 V emf is induced in the loop Calculate the diameter of the loop of wire (Give your answer in meters but don't include the units)
c=3 x 108 m/s 0 = 8.85 x 10-12 Chapter 21 magnetic force on moving charge: F-g||||B magnetic force on straight current: |F| = IL|B| magnetic field produced by long current: |B| = Hol 2πr magnetic field produced by loop current: Boenter] =Nol 2R E =-NAB At E=cB Chapter 22 Emotional=vBL C² N.m² Erms U= E² Chapter 20 Emax √2 Ho B² 140=4 x 10-7T m A = BA cos 0 S Brms= 11 P A Bar √2 <= cu