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A thin biconvex lens (labelled Ll in the figure) having a focal length of 61 cm is located at a distance d = 225 cm in front (i.e., to the left) of a thin biconcave lens (labelled L2 in the figure) of focal length 61 cm, as shown in the figure. L1 L2 Pencil S01 d = A pencil is situated at a distance Sol - 150 cm to the left of the positive lens. We will denote this pencil by "OBJECT 1". a) [5 points] The image of the pencil formed by Ll is located at a distance Sil from Ll. Calculate Sil.
Sil = ► 102.81 cm b) [5 points) The previous image from part a) is now treated as the object of L2. We will denote this object by "OBJECT 2". Assume Sil 85.67 cm and determine the distance S.2 between "OBJECT 2" and L2. So2 = -35.63 cm c) [5 points] Consider 5.2 = 116.1 cm . The image of "OBJECT 2" formed by L2 is located at a distance Si2 from L2. Calculate Si2 a Si2 = -39.99 cm >
- - d) [5 points) If S01 - 150 cm, Sil = 85.67 cm, S.2 116.1 cm and Si2 = -36. 35 cm calculate the total magnification MT obtained from the optical system formed by Ll and L2. Mi = -0.18