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In the figure below, an iron bar sitting on two parallel copper rails, connected to each other by a resistor, is pulled

Posted: Sun Apr 17, 2022 3:54 pm
by answerhappygod
In the figure below, an iron bar sitting on two parallel copper
rails, connected to each other by a resistor, is pulled to the
right with a constant force of magnitude
Fapp = 1.15 N.
The friction between the bar and rails is negligible. The
resistance
R = 8.00 Ω,
the bar is moving at a constant speed of 2.05 m/s, the distance
between the rails is ℓ, and a uniform magnetic field
B
is directed into the page.
Two parallel horizontal rails are vertically aligned and
connected on their left ends by a wire. A resistor R is in
the middle of the wire. The rails are separated by a distance ℓ. A
bar lies vertically across the middle of the rails, to the right of
the wire. An arrow labeled Fapp extends from
the middle of the bar to the right.
(a)
What is the current through the resistor (in A)?
A
(b)
If the magnitude of the magnetic field is 2.80 T, what is the
length ℓ (in m)?
m
(c)
What is the rate at which energy is delivered to the resistor
(in W)?
W
(d)
What is the mechanical power delivered by the applied constant
force (in W)?
W
What If? Suppose the magnetic field has an
initial value of 2.80 T at time
t = 0
and increases at a constant rate of 0.500 T/s. The bar starts at
an initial position
x0 = 0.100 m
to the right of the resistor at
t = 0,
and again moves at a constant speed of 2.05 m/s. Derive
time-varying expressions for the following quantities.
(e)
the current through the 8.00 Ω resistor R (Use the
following as necessary: t. Assume I(t)
is in A and t is in s. Do not include units in your
answer.)
I(t) =
A
(f)
the magnitude of the applied force
Fapp
required to keep the bar moving at a constant speed (Use the
following as necessary: t. Assume
Fapp(t) is in N and t is in
s. Do not include units in your answer.)
Fapp(t) =
N