Please solve this problem, I want to check if my answers are correct: use the formula sheet provided below My answers: a
Posted: Sun Apr 17, 2022 3:51 pm
Please solve this problem, I want to check if my
answers are correct:
use the formula sheet provided below
My answers:
a- Si(1) = 222 cm
b- So(2) = 210 - 185 = 25 cm
c- Si(2) = - 16.25 cm
d- M = - 1.182
Problem 5 (20 points) For the parts of the below question, fill in the empty boxes with your answer (YOUR ANSWER MUST BE ONLY A NUMBER; DO NOT WRITE UNITS; DO NOT WRITE LETTERS). A thin biconvex lens (labelled in the figure) having a focal length of 74 cm is located at a distance d = 210 cm in front (i.e, to the left) of a thin biconcave lens (labelled L2 in the figure) of focal length 74 cm, as shown in the figure L2 ܝܪ Pencil So1 d A pencil is situated at a distance 5,1 = 111 cm to the left of the positive lens. We will denote this pencil by "OBJECT 1". a) (5 points) The image of the pencil formed by Ll is located at a distance si from Ll. Calculate 811- 8,1 = cm b) (5 points. The previous image from part a) is now treated as the object of L2 We will denote this object by "OBJECT 2". Assume 811 = 185 cm and determine the distances between "OBJECT 2" and L2 8.2 = c) (5 points] Consider 32 = 20.83 cm. The image of "OBJECT 2* formed by L2 is located at a distance s from L2. Calculate sig. 8,9 d) (5 points) If Bol = 111 cm, sa = 185 cm, 8 = 20.83 cm and 819 = -14.78 cm calculate the total magnification My obtained from the optical system formed by L1 and L.2. M7=
Chapter 5 = c= 3 108 m/s Mo = 12.56 x 10-7 T.m/A Eo = 8.85 x 10-12 C2/N.m2 h = 6.626 X 10-34 4 J. is = V W = = 2nf 217 = T 18 2 n = λ n k =* v= = 11 af f = Lenses += * = -1) (4 m) M = - => (^? 1 1 1 1 : nl Si - yi So Si f f nm R1 R2 So yo (Converging (Convex) lense:f > 0) (Diverging (Concave) lense: f < 0) Meaning Associated with the Signs of lens Parameters Quantity Sign + S. Real Object Virtual Object Si Real Image Virtual Image y. Erect Object Inverted Object Yi Erect Image Inverted Image M Erect Image Inverted Image f Convex lens Concave lens
answers are correct:
use the formula sheet provided below
My answers:
a- Si(1) = 222 cm
b- So(2) = 210 - 185 = 25 cm
c- Si(2) = - 16.25 cm
d- M = - 1.182
Problem 5 (20 points) For the parts of the below question, fill in the empty boxes with your answer (YOUR ANSWER MUST BE ONLY A NUMBER; DO NOT WRITE UNITS; DO NOT WRITE LETTERS). A thin biconvex lens (labelled in the figure) having a focal length of 74 cm is located at a distance d = 210 cm in front (i.e, to the left) of a thin biconcave lens (labelled L2 in the figure) of focal length 74 cm, as shown in the figure L2 ܝܪ Pencil So1 d A pencil is situated at a distance 5,1 = 111 cm to the left of the positive lens. We will denote this pencil by "OBJECT 1". a) (5 points) The image of the pencil formed by Ll is located at a distance si from Ll. Calculate 811- 8,1 = cm b) (5 points. The previous image from part a) is now treated as the object of L2 We will denote this object by "OBJECT 2". Assume 811 = 185 cm and determine the distances between "OBJECT 2" and L2 8.2 = c) (5 points] Consider 32 = 20.83 cm. The image of "OBJECT 2* formed by L2 is located at a distance s from L2. Calculate sig. 8,9 d) (5 points) If Bol = 111 cm, sa = 185 cm, 8 = 20.83 cm and 819 = -14.78 cm calculate the total magnification My obtained from the optical system formed by L1 and L.2. M7=
Chapter 5 = c= 3 108 m/s Mo = 12.56 x 10-7 T.m/A Eo = 8.85 x 10-12 C2/N.m2 h = 6.626 X 10-34 4 J. is = V W = = 2nf 217 = T 18 2 n = λ n k =* v= = 11 af f = Lenses += * = -1) (4 m) M = - => (^? 1 1 1 1 : nl Si - yi So Si f f nm R1 R2 So yo (Converging (Convex) lense:f > 0) (Diverging (Concave) lense: f < 0) Meaning Associated with the Signs of lens Parameters Quantity Sign + S. Real Object Virtual Object Si Real Image Virtual Image y. Erect Object Inverted Object Yi Erect Image Inverted Image M Erect Image Inverted Image f Convex lens Concave lens