Answer Happy

Please solve this problem, I want to make sure my answers
are correct:
(Please use the formula sheet below when solving the
problem)
Problem 1 (20 points) For the parts of the below question, fill in the empty boxes with your answer (YOUR ANSWER MUST BE ONLY A NUMBER; DO NOT WRITE UNITS; DO NOT WRITE LETTERS). As shown in the figure below, a biconvex thin lens located 122 cm from a screen, projects onto it an image magnified relative to the object, where the transverse magnification is -0.15. yo Object Lens Screen a) [5 points] Determine the distance 8, from the object to the lens. 8, Пст b) [5 points) Assume the object is now at a distance of 537.9 cm to the lens. Calculate the new transverse magnification MThem- MTnew = c) (5 points] Consider 3. = 537.9 cm and s; = 110.9 cm. Determine the focal length f of the lens f= ста d) (5 points) If this lens was replaced by a convex mirror having a radius of curvature of 26 cm, what would be its focal length mirror? mirror = cm
Chapter 5 = c= 3 108 m/s Mo = 12.56 x 10-7 T.m/A Eo = 8.85 x 10-12 C2/N.m2 h = 6.626 X 10-34 4 J. is = V W = = 2nf 217 = T 18 2 n = λ n k =* v= = 11 af f = Lenses += * = -1) (4 m) M = - => (^? 1 1 1 1 : nl Si - yi So Si f f nm R1 R2 So yo (Converging (Convex) lense:f > 0) (Diverging (Concave) lense: f < 0) Meaning Associated with the Signs of lens Parameters Quantity Sign + S. Real Object Virtual Object Si Real Image Virtual Image y. Erect Object Inverted Object Yi Erect Image Inverted Image M Erect Image Inverted Image f Convex lens Concave lens