Consider the two ways of evaluating x: x = (200011.52 – 2.00011.752) and x = (200011.5 + 200011.75)(200011.5 – 200011.75

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Consider the two ways of evaluating x: x = (200011.52 – 2.00011.752) and x = (200011.5 + 200011.75)(200011.5 – 200011.75

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Consider The Two Ways Of Evaluating X X 200011 52 2 00011 752 And X 200011 5 200011 75 200011 5 200011 75 1
Consider The Two Ways Of Evaluating X X 200011 52 2 00011 752 And X 200011 5 200011 75 200011 5 200011 75 1 (58.26 KiB) Viewed 47 times
Consider the two ways of evaluating x: x = (200011.52 – 2.00011.752) and x = (200011.5 + 200011.75)(200011.5 – 200011.75) on a computer. Give an expression for computing the relative error in computing x using the standard model of floating point arithmetic described in the section 1.2 lecture. Which computation is likely to be more accurate? Justify your answer.
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