Answer Happy

Consider the following function and closed interval. f(x)=√3x, [-22, 3] Is f continuous on the closed interval [-22, 3]? ⒸYes O No If f is differentiable on the open interval (-22, 3), find f'(x). (If it is not differentiable on the open interval, enter DNE.) f'(x) = Find f(-22) and f(3). f(-22) = f(3) = f(b) f(a) b-a Find f(b) f(a) b-a Determine whether the Mean Value Theorem can be applied to f on the closed interval [a, b]. (Select all that apply.) Yes, the Mean Value Theorem can be applied. for [a, b] [-22, 3]. C = No, because f is not continuous on the closed interval [a, b]. No, because f is not differentiable in the open interval (a, b). None of the above. If the Mean Value Theorem can be applied, find all values of c in the open interval (a, b) such that f'(c) = f(b) f(a). If the Mean Value Theorem cannot be applied, explain why not. (Enter your answers as a comma-separated list. If the Mean Value Theorem cannot be applied, enter NA.) b-a