Find the integrating factor u(t) for the following linear differential equation. y' + 7y = 0 Op(t) = e-7 Ομ(t) = 7t Ou(t
Posted: Tue Sep 07, 2021 7:22 am
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Solve the following differential equation using an integrating factor. y' + 7y = 0 Oy(t) = Ce-7 Oy(t) = e-71 + Oy(t) = Cet? Oy(t) = Ce?
Find the integrating factor (t) to solve the initial value problem ty' + 4y = 612 – 5t; y(1) Ou(t) = 24 10u(t) = Ou(t) = 14 (1) = 64
Find the particular solution to the initial value problem. ty' + 4y = 62° - 5t; y(1) = 5 Oy(t) = 12 - + - 514 Oy(t) = 12 – 1 +514 Oy(t) = 12 - + - 51-4 Oy(t) = 12 - +51-4
Solve the following differential equation by using an integrating factor. y' = 13y Oy(t) = Ce131 Oy(t) = -1e-131 + c Oy(t) = €131+ c Oy(t) = Ce-13: Oy(t) = 1 131 + c y(t) = e-134 + c
Solve the differential equation by using an integrating factor:y' + 5y = x8 e -5x xºe5x + Ce5x Dox x + Cex bxºe-5x + Ce-5x bxºe$x + C Otxºe-5x + c 5x'e-5x + Ce-sx
Solve the differential equation by using an integrating factor: y' + (**)y = 0, y(1) = 4 Oy(x) = 4x-el- Oy(x) = 4x@el- Oy(x) = 4x®et-1 O y(x) = 4xer-6 Oy(x) = -4x-el- Oy(x) = -43-7el->