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[-/4.42 Points] DETAILS BBUNDERSTAT127.1.015. MY NOTES ASK YOUR TEACHER Allen's hummingbird (Selesphorus sesin) has been

Posted: Wed Jul 06, 2022 12:19 pm
by answerhappygod
4 42 Points Details Bbunderstat127 1 015 My Notes Ask Your Teacher Allen S Hummingbird Selesphorus Sesin Has Been 1
4 42 Points Details Bbunderstat127 1 015 My Notes Ask Your Teacher Allen S Hummingbird Selesphorus Sesin Has Been 1 (82.87 KiB) Viewed 7 times
[-/4.42 Points] DETAILS BBUNDERSTAT127.1.015. MY NOTES ASK YOUR TEACHER Allen's hummingbird (Selesphorus sesin) has been studied by zoologist Bill Alther. Suppose a small group of 10 Allen's hummingbirds has been under study in Arizons. The average weight for these birds is x 3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with 0.38 gram. (e) Find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the mergin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error (b) What conditions are necessary for your calculations? (Select all that apply.) ✔ is unknown n is large uniform distribution of weights is known normal distribution of weights (c) Interpret your results in the context of this problem. The probability that this interval contains the true average weight of Allen's hummingbirds is 0.80. The probability that this interval contains the true average weight of Allen's hummingbirds is 0.20. We are 80% confident that the true average weight of Allen's hummingbirds falls within this interval. We are 20% confident that the true average weight of Allen's hummingbirds falls within this interval. (d) Find the sample size necessary for an 80% confidence level with a maximal margin of amor E 0.08 for the mean weights of the hummingbirds. (Round up to the nearest whole number:) hummingbirds [-/4.42 Points] DETAILS BBUNDERSTAT127.1.016.MI. MY NOTES ASK YOUR TEACHER Overproduction of uric acid in the body can be an indication of call breakdown. This may be an advance indication of illness such as gout, leukemia, or lymphoma.† Over a period of months, an adult male patient has taken eleven blood tests for uric acid. The mean concentration was 5.30 mg/dl. The distribution of uric acid in healthy adult males can be assumed to be normal, with a 1.81 mg/dl. (a) Find a 95% confidence interval for the population meen concentration of uric acid in this patient's bload. What is the margin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error (b) What conditions are necessary for your calculations? (Select all that apply.) is known is unknown uniform distribution of uric acid normal distribution of uric acid is large (c) Interpret your results in the context of this problem We are 95% confident that the true uric acid level for this patient falls within this interval. The probability that this interval contains the true average uric acid level for this patient is 0.95. The probability that this interval contains the true average uric acid level for this patient is 0.05. We are 5% confident that the true uric acid level for this patient fals within this interval. (d) Find the sample size necessary for a 95% confidence level with maximal margin of error E1.04 for the meen concentration of uric acid in this patient's blood. (Round your answer up to the nearest whole number.) blood tests