Solve the equation by separation of variables. dy 12-21 dt y2 Oy= Vt3 – 3t2 + C Oy= V13 + 3t2 + c Oy= V13 – 312 Oy3 = V1
Posted: Tue Sep 07, 2021 7:22 am
- Solve The Equation By Separation Of Variables Dy 12 21 Dt Y2 Oy Vt3 3t2 C Oy V13 3t2 C Oy V13 312 Oy3 V1 1 (32.33 KiB) Viewed 90 times
- Solve The Equation By Separation Of Variables Dy 12 21 Dt Y2 Oy Vt3 3t2 C Oy V13 3t2 C Oy V13 312 Oy3 V1 2 (24.56 KiB) Viewed 90 times
- Solve The Equation By Separation Of Variables Dy 12 21 Dt Y2 Oy Vt3 3t2 C Oy V13 3t2 C Oy V13 312 Oy3 V1 3 (32.04 KiB) Viewed 90 times
- Solve The Equation By Separation Of Variables Dy 12 21 Dt Y2 Oy Vt3 3t2 C Oy V13 3t2 C Oy V13 312 Oy3 V1 4 (31.57 KiB) Viewed 90 times
- Solve The Equation By Separation Of Variables Dy 12 21 Dt Y2 Oy Vt3 3t2 C Oy V13 3t2 C Oy V13 312 Oy3 V1 5 (36.83 KiB) Viewed 90 times
Solve the differential equation by separation of variables. Leave your solution in implicit form.y' 2x+3 7y +1 Oy + y = x2 + 3x + C Oy? + y = x2 + 4x + C Oy? = x2 + x + c O y = x2 + 3x + c Oy6 = x2 + 3x + C Oy? + y = x2 + 3x + C
Solve for the general solution by separation of variables. dy x = 5y dx Oy(x) = C&x ©y(x) = + C y(x) = e3x + C Oy(x) = 5x + C Oy(x) = Cxs Oy(x) = C1x2 Oy(x) = x + ec
Solve the initial value problem by separation of variables. 3х2 3y2 +1' = 1 Oy3 + 3y = 3x3 + 1 Oy2 + y - x3 = 1 Oy3 + y = 3x + 2 Oy3 + y - x3 = 0
Solve the differential equation by separation of variables: y' = 6xy?, y(0) = 1 Oy = 1 3x2+10 1 3x2+10 1 y = Oy = 10x2_3 Oy = 3x2 + 10 Oy = -3x2 + 10 Oy = 3x2-10