a) Karen wants to advertise how many chocolate chips are in each Big Chip cookie at her bakery. She randomly selects a s
Posted: Wed Jul 06, 2022 12:14 pm
a) Karen wants to advertise how many chocolate chips are ineach Big Chip cookie at her bakery. She randomly selects a sampleof 61 cookies and finds that the number of chocolate chips percookie in the sample has a mean of 8.9 and a standard deviation of1.9. What is the 95% confidence interval for the number ofchocolate chips per cookie for Big Chip cookies? Enter your answersaccurate to one decimal place (because the sample statistics arereported accurate to one decimal place).
b) You intend to estimate a population mean with aconfidence interval. You believe the population to have a normaldistribution. Your sample size is 15.While it is an uncommon confidence level, find the critical valuethat corresponds to a confidence level of 96%.(Report answer accurate to three decimal places withappropriate rounding.)c) Assume that a sample is used to estimate a populationmean μμ. Find the margin of error M.E. thatcorresponds to a sample of size 10 with a mean of 59.4 and astandard deviation of 8.6 at a confidence level of 90%.Report ME accurate to one decimal place because the samplestatistics are presented with this accuracy.M.E. = Answer should be obtained without any preliminary rounding.However, the critical value may be rounded to 3 decimal places.
d) Assume that a sample is used to estimate a populationmean μμ. Find the 99% confidence interval for a sample of size57 with a mean of 50.3 and a standard deviation of 8.7. Enter youranswer asan open-interval (i.e.,parentheses) accurate to one decimal place (because the samplestatistics are reported accurate to one decimal place).99% C.I. = Answer should be obtained without any preliminary rounding.However, the critical value may be rounded to 3 decimal places.
e) Assume that a sample is used to estimate a populationmean μμ. Find the 90% confidence interval for a sample of size571 with a mean of 51.8 and a standard deviation of 20.4. Enteryour answer as a tri-linear inequality accurate to one decimalplace (because the sample statistics are reported accurate to onedecimal place).
< μμ <
Answer should be obtained without any preliminary rounding.However, the critical value may be rounded to 3 decimal places.
b) You intend to estimate a population mean with aconfidence interval. You believe the population to have a normaldistribution. Your sample size is 15.While it is an uncommon confidence level, find the critical valuethat corresponds to a confidence level of 96%.(Report answer accurate to three decimal places withappropriate rounding.)c) Assume that a sample is used to estimate a populationmean μμ. Find the margin of error M.E. thatcorresponds to a sample of size 10 with a mean of 59.4 and astandard deviation of 8.6 at a confidence level of 90%.Report ME accurate to one decimal place because the samplestatistics are presented with this accuracy.M.E. = Answer should be obtained without any preliminary rounding.However, the critical value may be rounded to 3 decimal places.
d) Assume that a sample is used to estimate a populationmean μμ. Find the 99% confidence interval for a sample of size57 with a mean of 50.3 and a standard deviation of 8.7. Enter youranswer asan open-interval (i.e.,parentheses) accurate to one decimal place (because the samplestatistics are reported accurate to one decimal place).99% C.I. = Answer should be obtained without any preliminary rounding.However, the critical value may be rounded to 3 decimal places.
e) Assume that a sample is used to estimate a populationmean μμ. Find the 90% confidence interval for a sample of size571 with a mean of 51.8 and a standard deviation of 20.4. Enteryour answer as a tri-linear inequality accurate to one decimalplace (because the sample statistics are reported accurate to onedecimal place).
< μμ <
Answer should be obtained without any preliminary rounding.However, the critical value may be rounded to 3 decimal places.