5. [-/4 Points] DETAILS The shear strength of each of ten test spot welds is determined, yielding the following data (ps
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5. [-/4 Points] DETAILS The shear strength of each of ten test spot welds is determined, yielding the following data (ps
question. Need Help? Read It ASK YOUR TEACHER (b) Again assuming a normal distribution, estimate the strength value below which 95% of all welds will have their strengths. [Hint: What is the 95th percentile in terms of u and o? Now use the invariance principle.] (Round your answer to two decimal places.) psi Watch It PRACTICE ANOTHER (c) Suppose we decide to examine another test spot weld. Let X = shear strength of the weld. Use the given data to obtain the mle of P(X ≤ 400). [Hint: P(X ≤ 400) = ((400 – µ)/o).] (Round your answer to four decimal places.)
5. [-/4 Points] DETAILS The shear strength of each of ten test spot welds is determined, yielding the following data (psi). 358 389 362 409 415 370 367 408 366 375 DEVORESTAT9 6.2.025. average standard deviation (a) Assuming that shear strength is normally distributed, estimate the true average shear strength and standard deviation of shear strength using the method of maximum likelihood. (Round your answers to two decimal places.) psi psi Submit Answer MY NOTES You may need to use the appropriate table in the Appendix of Tables to answer this