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Using end behaviours, turning points, and zeros, determine the polynomial equation that represents the graph shown below. -5432 a) 4 3 4 5 g(x) --4x² - 2x² + 3x + 1 C) b) g(x) = 4x² - 2x² + 3x+1 - g(x) = -4x² - 3x²³ - 2x² + 3x + 1 d) g(x) --4x² + 3x+1 D
An equation for a quartic function with zeros 4, 5, and 6 that passes through the point (7, 18) is a) y = (x-6)²(x-4)(x - 5) Ob) y--(x-4)(x-5)²(x-6)² c) y = (x-4)(x - 5)(x-6) d) y = (x-4)²(x - 5)(x - 6)