Solve the initial value problem. (2) =-xe, (0)= 1 (b) (c) (d) "(√) -¹ =1 = zsin 2², y = tanr, y(*/4) = 3 = ¹, y(2)=-1, (
Posted: Wed Jul 06, 2022 12:05 pm
Solve the initial value problem. (2) =-xe, (0)= 1 (b) (c) (d) "(√) -¹ =1 = zsin 2², y = tanr, y(*/4) = 3 = ¹, y(2)=-1, (2)=-1 (0) = 1 = x², y(0) = 7, = -sinz, y(0)=1. "²e", (0) 1, (0)-2, (e) (0) (g) (0) 3 (h) "=2+sin 2r, y(0)-1, (0)=-6. "(0) 3 (i) "2+1, (2) 1. (2)=-4, /'(2)=7 (0)=-3