Answer Happy

How many computers? In a simple random sample of 130 households, the sample mean number of personal computers was 1.79. Assume the population standard deviation is = 0.61. Part: 0 / 4 Part 1 of 4 (a) Construct a 99% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places. A 99% confidence interval for the mean number of personal computers is 1 Part: 1/4 Part 2 of 4 (b) If the sample size were 110 rather than 130, would the margin of error be larger or smaller than the result in part (a)? Explain. The margin of error would be larger will decrease Part: 2/4 the standard error. since a decrease in the sample size
Part 3 of 4 (c) If the confidence levels were 95% rather than 99%, would the margin of error be larger or smaller than the result in part (a)? Explain. The margin of error would be smaller level will increase Part: 3 / 4 Part 4 of 4 the critical value Za/2. since an increase in the confidence X Ś (d) Based on the confidence interval constructed in part (a), is it likely that the mean number of personal computers is greater than 1.47 ? It (Choose one) likely that the mean number of personal computers is greater than 1.47.