However, if we change the definition of vector addition to: u v = (₁, U₂) (V₁, V₂) = (U₁ + V₁, U₂ + V₂ = b) and definiti
Posted: Wed Jul 06, 2022 11:52 am
statement by confirming that all ten axioms in the definition of a vector space are true for all vectors in the set.
However, if we change the definition of vector addition to: u v = (₁, U₂) (V₁, V₂) = (U₁ + V₁, U₂ + V₂ = b) and definition of scalar multiplication to: cu = c (₁, ₂) = (cu₁, cu₂ - cb + b) the set S₂ is a vector space. Verify this