The solution of a certain differential equation is of the form y(t) = a exp(lt) + bexp(3t), where a and b are constants.
Posted: Wed Jul 06, 2022 11:49 am
The solution of a certain differential equation is of the form y(t) = a exp(lt) + bexp(3t), where a and b are constants. The solution has initial conditions y(0) = 5 and 3/(0) = 4. Find the solution by using the initial conditions to get linear equations for a and b. y(t) =