Answer Happy

Posted: **Wed Jul 06, 2022 11:35 am**

: 5 Gamy Nowo 20cutto Un Concerte Ne Table Sum Of Forces Fnet Fnet X Fapp Ffr Ma Fnet Y Fn Fg 0 Using Ffr 1 (66.35 KiB) Viewed 14 times

: 5 Gamy Nowo 20cutto Un Concerte Ne Table Sum Of Forces Fnet Fnet X Fapp Ffr Ma Fnet Y Fn Fg 0 Using Ffr 2 (21.41 KiB) Viewed 14 times

5 . gamy nowo 20CUTTO Un concerte ne table. "Sum of forces"= Fnet Fnet x = Fapp-Ffr=ma, - Fnet y = Fn-Fg = 0 Using Ffr = HkFN = Hk (mg) calculate the value of the coefficient of fric the value in the table. m (kg) For the following trials keep the wood box on the floor and add on top of it objec reach the values of the masses indicated in the table. Increase the applied force su Forces" as at least 20N. 50 100 Paragraph 130 140 Fapp(N) 118N 209N 303N 288N Ffr(N) 94N 188N Styles ICTUSIVIT UT I VOA VI TU 244N 263N a (m/s²) Hk
Keep the 50 kg box on the floor and applied force of 160N. Calculate the coefficient of friction and acceleration changing the "friction" level 3 times between "None" and Lots". "Sum of Forces" is at least 20 N. m(kg) 50 50 50 Fa (N) 160 160 160 Ffr (N) 114N 46N 169N a (m/s) Pa