Answer Happy

Figure 3.2.1 Horizontal line Figure 3.2.2 Horizontal line + 75 μC + 75 μC. 0.35 m 0.35 m + 48 μC + 48 μC 0.25 m 0.35 m New position 0.35 m – 85 μC · 85 μC b. Refer to Figure 3.2.1 for (i) & (ii): Three particles of charge + 75 µC, + 48 µC and - 85 µC are placed in a line. The center charge of +48 µC is 0.35 m from each of the other two charges. (Coulomb's constant, k = 9.00 × 10⁹ Nm²/C²). Based on this information, answer the following: (i) What is the net force on the + 48 µC charge due to the other two charges? (ii) What is the net force on the + 75 µC charge due to the other two charges? (iii) Refer to Figure 3.2.2. If the + 48 µC charge is raised 0.25 m (vertically upwards) from the horizontal line to a new position while the other two charges remain in the same position, what is the new net force on this + 48 µC charge due to the other two charges? (8 x ½ mark) (4 × ½ mark) (4 × ½ mark)