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(Figure 1) Consider a lawnmower of mass m which can slide across a horizontal surface with a coefficient of friction μl. In this problem the lawnmower is pushed using a massless handle, which makes an angle with the horizontal. Assume that Fh, the force exerted by the handle, is parallel to the handle. Take the positive x direction to be to the right and the postive y direction to be upward. Use g for the magnitude of the acceleration due to gravity. Figure 16E 0 1 of 1 >
Part A Find the magnitude, Fh, of the force required to slide the lawnmower over the ground at constant speed by pushing the handle. Express the required force in terms of given quantities. ▸ View Available Hint(s) umg Fh= cose-usine Submit Previous Answers ✓ Correct
Part B The solution for F has a singularity (that is, becomes infinitely large) at a certain angle critical For any angle > critical, the expression for Fh will be negative. However, a negative applied force F would reverse the direction of friction acting on the lawnmower, and thus this is not a physically acceptable solution. In fact, the increased normal force at these large angles makes the force of friction too large to move the lawnmower at all. Find an expression for tan (@critical). ▸ View Available Hint(s) tan (@critical) = μ ΨΕΙ ΑΣΦ VO Submit Previous Answers Request Answer X Incorrect; Try Again ISAAC ?