ght 4e A
Posted: Wed Jul 06, 2022 11:27 am
- Ght 4e A Ps 3 Pushing A Lawnmower Figure 1 Consider A Lawnmower Of Mass M Which Can Slide Across A Horizontal Surface 1 (31.58 KiB) Viewed 12 times
- Ght 4e A Ps 3 Pushing A Lawnmower Figure 1 Consider A Lawnmower Of Mass M Which Can Slide Across A Horizontal Surface 2 (28.21 KiB) Viewed 12 times
- Ght 4e A Ps 3 Pushing A Lawnmower Figure 1 Consider A Lawnmower Of Mass M Which Can Slide Across A Horizontal Surface 3 (36.79 KiB) Viewed 12 times
ght 4e A <PS 3 Pushing a Lawnmower (Figure 1) Consider a lawnmower of mass m which can slide across a horizontal surface with a coefficient of friction μ. In this problem the lawnmower is pushed using a massless handle, which makes an angle with the horizontal. Assume that F, the force exerted by the handle, is parallel to the handle. Take the positive x direction to be to the right and the postive y direction to be upward. Use g for the magnitude of the acceleration due to gravity. Figure 1 of 1
on of 1 > Part A umg Fh= cos usin Find the magnitude, Fh. of the force required to slide the lawnmower over the ground at constant speed by pushing the handle. Express the required force in terms of given quantities. ▸ View Available Hint(s) Submit Previous Answers Correct Part B 3 of 6 > Review | Constants The solution for F has a singularity (that is, becomes infinitely large) at a certain angle
e f 1 Correct Part B The solution for F has a singularity (that is, becomes infinitely large) at a certain angle critical For any angle > critical, the expression for Fh will be negative. However, a negative applied force Fh would reverse the direction of friction acting on the lawnmower, and thus this is not a physically acceptable solution. In fact, the increased normal force at these large angles makes the force of friction too large to move the lawnmower at all. Find an expression for tan (@critical). ▸ View Available Hint(s) IVE ΑΣΦ tan(critical) = μ Submit Previous Answers Request Answer X Incorrect; Try Again ?
Posted: Wed Jul 06, 2022 11:27 am
- Ght 4e A Ps 3 Pushing A Lawnmower Figure 1 Consider A Lawnmower Of Mass M Which Can Slide Across A Horizontal Surface 1 (31.58 KiB) Viewed 12 times
- Ght 4e A Ps 3 Pushing A Lawnmower Figure 1 Consider A Lawnmower Of Mass M Which Can Slide Across A Horizontal Surface 2 (28.21 KiB) Viewed 12 times
- Ght 4e A Ps 3 Pushing A Lawnmower Figure 1 Consider A Lawnmower Of Mass M Which Can Slide Across A Horizontal Surface 3 (36.79 KiB) Viewed 12 times
on of 1 > Part A umg Fh= cos usin Find the magnitude, Fh. of the force required to slide the lawnmower over the ground at constant speed by pushing the handle. Express the required force in terms of given quantities. ▸ View Available Hint(s) Submit Previous Answers Correct Part B 3 of 6 > Review | Constants The solution for F has a singularity (that is, becomes infinitely large) at a certain angle
e f 1 Correct Part B The solution for F has a singularity (that is, becomes infinitely large) at a certain angle critical For any angle > critical, the expression for Fh will be negative. However, a negative applied force Fh would reverse the direction of friction acting on the lawnmower, and thus this is not a physically acceptable solution. In fact, the increased normal force at these large angles makes the force of friction too large to move the lawnmower at all. Find an expression for tan (@critical). ▸ View Available Hint(s) IVE ΑΣΦ tan(critical) = μ Submit Previous Answers Request Answer X Incorrect; Try Again ?