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Problem 24. (20 pts) In this problem I will lead you through a calculation of the ionization energy of the ground state of hydrogen. Hydrogen consists of one proton and one electron. In a simplistic model, the electron is taken to be in circular orbit around the proton. In the “ground state” of the atom the radius of this orbit is ro= 5.29 × 10-¹1 m. A) Find the potential energy of the electron (relative to zero potential energy at r=∞o) when it is in its ground state orbit. Express your answer in eV. B) Find the kinetic energy of the electron when it is in its ground state circular orbit. To do this note that in circular orbit, along the radial direction (outward positive) F=ma⇒ k|qe apl r² k|qe apl v². = 2ro 1 -me 2 = -me (2) ro Express your answer in eV. C) The ionization energy is the difference in the energy (Kinetic Energy+ Potential Energy) of the ground state and the energy that the electron has when it is infinitely far away from the proton with zero kinetic energy. Find the ionization energy. Express your answer in eV. (Answer: 13.6 eV).