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Find the potential difference across each resistor in the figure below. (R₁ = 4.650, R₂ = 4.100, R₂ = 3.300, R₂ = 2.300) 18.0 V 12.0 V or R₁2 12.0 V Step 1 Assume that the currents I₁, I₂, and I are in the directions indicated by the arrows in the figure redrawn below. (Enter your answers to at least four significant figures.) 1₂ 3.00 V 18.0 V R₁ Solving for I, gives 1₁₂ = 1₁ = R₂ 9 R₂₂ a R₁ 3.00 V Applying Kirchhoff's junction rule at a gives [1] 13 = 1₁ + 1₂. Using Kirchhoff's loop rule starting at point a and going clockwise around the leftmost loop yields -3.00 V - R₂13-R₁₁ + 12.0 V = 0. 1.9354✔ R₁Z R3 R₁ Rs Ⓡ 31 1.935 A) - (0.8817✔ 0.88173 [2]
Step 2 Starting at point a and going counterclockwise around the rightmost loop, we find that Kirchhoff's loop rule gives -3.00 V - R₂3 - (R₂ + R₂)₂ + 18.0 V = 0. 1₁ or 12.0 V Step 3 1₂ = T 1₂ = R₁ ww R₂ Ⓡ Solving for I₂, we have the following. (Enter your answers to at least four significant figures.) ) - (R₂²+2 R₂) ²3² 31 R₂ 2.6785✔ R₂ + R₂ I3 = 1₁ + 1₂ = a 12₂ Solving for I, we obtain 1₂ = 4.682 3.00 V 18.0 V 13 15 R₁ 2.679 Substituting Equations [2] and [3] in Equation [1] from the previous two steps and collecting terms, we have the following. (Enter your answers to at least four significant figures.) 21 Your response differs from the correct answer by more than 100%. A) - 0.7321✔ xA) 0.7321 A. [3]