- For The Equilibrium 21br G 12 G Br G Kc 8 50 10 At 150 C If 0 0430 Mol Of Ibr Is Placed In A 1 0 L Containe 1 (19.47 KiB) Viewed 16 times
For the equilibrium 21Br(g) 12(g) + Br₂(g) Kc = 8.50 × 10-³ at 150°C. If 0.0430 mol of IBr is placed in a 1.0-L containe
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For the equilibrium 21Br(g) 12(g) + Br₂(g) Kc = 8.50 × 10-³ at 150°C. If 0.0430 mol of IBr is placed in a 1.0-L containe
For the equilibrium 21Br(g) 12(g) + Br₂(g) Kc = 8.50 × 10-³ at 150°C. If 0.0430 mol of IBr is placed in a 1.0-L container, what is the partial pressure of l2(g) in atm after equilibrium is reached?