A student determines the value of the equilibrium constant to be 1.26 x 1064 for the following reaction. 2Na(s) + 2H₂O(l

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A student determines the value of the equilibrium constant to be 1.26 x 1064 for the following reaction. 2Na(s) + 2H₂O(l

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A Student Determines The Value Of The Equilibrium Constant To Be 1 26 X 1064 For The Following Reaction 2na S 2h O L 1
A Student Determines The Value Of The Equilibrium Constant To Be 1 26 X 1064 For The Following Reaction 2na S 2h O L 1 (50.02 KiB) Viewed 9 times
A student determines the value of the equilibrium constant to be 1.26 x 1064 for the following reaction. 2Na(s) + 2H₂O(l) -> 2NaOH(aq) + H₂(g) Based on this value of Keq: AG for this reaction is expected to be ✓than zero. Calculate the free energy change for the reaction of 1.86 moles of Na(s) at standard conditions at 298 K. AG kJ rxn
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