Compound W, C6H₁1Cl, undergoes base-promoted E2 elimination to form a single alkene Y. Under similar reaction conditions
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Compound W, C6H₁1Cl, undergoes base-promoted E2 elimination to form a single alkene Y. Under similar reaction conditions
Compounds X and Y are both C7H15Cl products formed in the radical chlorination of 2,4-dimethylpentane. Base-promoted E2 elimination of X and Y gives, in each case, a single C7H₁4 alkene. Both X and Y undergo an S№2 reaction with sodium iodide in acetone solution to give C7H15I products; in this reaction Y reacts faster than X. What is the structure of X? • Do not use stereobonds in your answer. • In cases where there is more than one possible structure for each molecule, just give one for each. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate structures with + signs from the drop-down menu. ● ChemDoodle Sn [F
Compounds X, C9H₁9Br, and Y, C9H19Cl, undergo base-promoted E2 elimination to give the same single alkene product, Z. Catalytic hydrogenation of Z affords 2,3,3-trimethylhexane. In water X readily reacts to give a substitution product, C9H19OH, together with Z. Y does not react with water. Propose structures for X and Y. . Do not use stereobonds in your answer. • In cases where there is more than one possible structure for each molecule, just give one for each. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate structures with + signs from the drop-down menu. ● ... ChemDoodle Sn [F Previous Next Save a