What is the [HA] (in mol L-¹) of a solution containing 1.464 mol L-¹ of a diprotic acid with PKA1 = 4.41 and PKA2 = 8.42
Posted: Wed Jul 06, 2022 11:04 am
What is the [HA] (in mol L-¹) of a solution containing 1.464 mol L-¹ of a diprotic acid with PKA1 = 4.41 and PKA2 = 8.42 ? Answer: H₂A + H₂O = H₂O* + HA HA + H₂O = H₂O+ + A²- PKA1 PKA2