The equilibrium constant, Ke, for the following reaction is 0.0180 at 698 K. 2HI(g) H₂(g) + 12 (g) Calculate the equilib
Posted: Wed Jul 06, 2022 11:03 am
The equilibrium constant, Ke, for the following reaction is 0.0180 at 698 K. 2HI(g) H₂(g) + 12 (g) Calculate the equilibrium concentrations of reactant and products when 0.234 moles of HI(g) are introduced into a 1.00 L vessel at 698 K. M M [H₂] = = M