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The equilibrium constant, K, for the following reaction is 1.80x102 at 698 K. 2HI(g) H₂(g) + 1₂(g) An equilibrium mixtur
Posted: Wed Jul 06, 2022 11:01 am
by answerhappygod
- The Equilibrium Constant K For The Following Reaction Is 1 80x102 At 698 K 2hi G H G 1 G An Equilibrium Mixtur 1 (72.95 KiB) Viewed 13 times
The equilibrium constant, K, for the following reaction is 1.80x102 at 698 K. 2HI(g) H₂(g) + 1₂(g) An equilibrium mixture of the three gases in a 1.00 L'flask at 698 K contains 0.303 M HI, 4.06x10-2 M H₂ and 4.06x102 M 1₂. What will be the concentrations of the three gases once equilibrium has been reestablished, if 2.56x102 mol of H₂(g) is added to the flask? [HI]