a) pH=1.95 [H2M]= 0.089 M [HM-] =1.12E-2M [M2-]=2.01E-6M b) pH=4.28 [H2M]=3.7E-3M [HM-]=0.100M [M2-]=3.8E-3M
Posted: Wed Jul 06, 2022 10:59 am
a) pH=1.95 [H2M]= 0.089 M [HM-] =1.12E-2M [M2-]=2.01E-6M
b) pH=4.28 [H2M]=3.7E-3M [HM-]=0.100M
[M2-]=3.8E-3M
10-5. We will abbreviate malonic acid, CH₂(CO₂H)2, as H₂M. Find the pH and concentrations of H₂M, HM, and M2- in (a) 0.100 M H₂M; (b) 0.100 M NaHM; (c) 0.100 M Na₂M.
b) pH=4.28 [H2M]=3.7E-3M [HM-]=0.100M
[M2-]=3.8E-3M
- A Ph 1 95 H2m 0 089 M Hm 1 12e 2m M2 2 01e 6m B Ph 4 28 H2m 3 7e 3m Hm 0 100m M2 3 8e 3m 1 (15.11 KiB) Viewed 10 times
- A Ph 1 95 H2m 0 089 M Hm 1 12e 2m M2 2 01e 6m B Ph 4 28 H2m 3 7e 3m Hm 0 100m M2 3 8e 3m 2 (15.11 KiB) Viewed 10 times