Answer Happy

Posted: **Wed Jul 06, 2022 10:57 am**

: M Naoh Im Hci Volume Of Naoh Volume Of Hci Total Volume After Mixing 0 0 1 0 2 0 3 0 4 0 5 0 6 0 6 5 7 0 75 8 0 8 5 Res 1 (40.67 KiB) Viewed 13 times

: M Naoh Im Hci Volume Of Naoh Volume Of Hci Total Volume After Mixing 0 0 1 0 2 0 3 0 4 0 5 0 6 0 6 5 7 0 75 8 0 8 5 Res 2 (34.61 KiB) Viewed 13 times

: M Naoh Im Hci Volume Of Naoh Volume Of Hci Total Volume After Mixing 0 0 1 0 2 0 3 0 4 0 5 0 6 0 6 5 7 0 75 8 0 8 5 Res 3 (19.34 KiB) Viewed 13 times

: M Naoh Im Hci Volume Of Naoh Volume Of Hci Total Volume After Mixing 0 0 1 0 2 0 3 0 4 0 5 0 6 0 6 5 7 0 75 8 0 8 5 Res 4 (30.03 KiB) Viewed 13 times

M NaOH+ IM HCI Volume of NaOH Volume of HCI Total volume after mixing 0.0 1.0 2,0 3.0 4.0 5.0 6.0 6.5 7.0 75 8.0 8.5 RESULTS Time (min) net ionic equation T₁ - T₂ - AT - T₂ - T₁ = 9- ΔΗ = Calculation 50ML 50ML NaOH 21.00 210c Temperature (°C) HCI 21.0c 21.00 20c Mixture 2600 270c 21.0c 27.0c 21.0- 21.0c
IM NaOH+ IM HAC Volume of NaOH Volume of HCI Total volume after mixing 0.0 1.0 2,0 3.0 4.0 5.0 6.0 6.5 7.0 7,5 8.0 8.5 Time (min) net ionic equation T₁ = T₂ - AT - T₂ - T₁ = 9- nw ΔΗ - Calculation 50ML 50 ML 100 ML NaOH 2100 21.0€ 21.0⁰ Temperature (°C) HAc 21.00 21.05 21.00 Mixture 250c 25.0c 250c 25.0c 2500
Postlab Questions: 1. Which of the reactions resulted in the largest heat of neutralization? Does this make sense? Why or why not? 2. Why is it important to wash and dry the thermometer in between readings of the temperature of the acid and of the base?
EM NHÀ TIN 11 Volume of NaOH Volume of HCI Total volume after mixing 00 1.0 20 30 40 50 6.0 6.5 7.0 7.5 80 8.5 Time (min) net lonic equation T₁ - T₁ - AT - T₁ - T₁ - 4- n- ΔΗ Calculation 76 ML GOL 100 ML NHI 21.0² 21.6 Temperature ("C) HCI 210 210 Mixture 25.09 2564 NH3(aq) + HCl(aq)->NH 4C1 (34)