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The equilibrium constant, K, for the following reaction is 1.80×102 at 698 K. 2HI(g) H₂(g) + I₂(9) An equilibrium mixtur
Posted: Wed Jul 06, 2022 10:57 am
by answerhappygod
- The Equilibrium Constant K For The Following Reaction Is 1 80 102 At 698 K 2hi G H G I 9 An Equilibrium Mixtur 1 (23.06 KiB) Viewed 18 times
The equilibrium constant, K, for the following reaction is 1.80×102 at 698 K. 2HI(g) H₂(g) + I₂(9) An equilibrium mixture of the three gases in a 1.00 L flask at 698 K contains 0.327 M HI, 4.39×10-2 M H₂ and 4.39x10-2 M I₂. What will be the concentrations of the three gases once equilibrium has been reestablished, if 0.190 mol of HI(g) is added to the flask? [HI] = [H₂] = [1₂] = ΣΣΣ