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للمعادلة التفاضلية التالية: ( Variation of parameters) x2 xy" + 4xy' +2y = x² +1 +
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للمعادلة التفاضلية التالية: ( Variation of parameters) x2 xy" + 4xy' +2y = x² +1 +
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Tue Sep 07, 2021 7:19 am
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answerhappygod
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للمعادلة التفاضلية التالية: ( Variation of parameters) x2 xy" + 4xy' +2y = x² +1 +