The solution of the boundary value problem (D2 +42)y=0,given that y(0) = 0 and y T = 1 Oy = cos 4 y = 3 sin 42 y = 4 sin
Posted: Mon Apr 11, 2022 6:01 am
The solution of the boundary value problem (D2 +42)y=0,given that y(0) = 0 and y T = 1 Oy = cos 4 y = 3 sin 42 y = 4 sin 4. Oy=sin 4.0