Answer Happy

The conservatory illustrated in Figure 1 has been retrofitted to the 15 m long southern facade of a stone-walled cottage in order to provide a sun space. The unventilated conservatory is 5 m high and 2.5 m in depth, with an opaque, insulated top cover and side walls. On a cloudy, but warm summer day with calm wind conditions the exterior (ambient) and interior (room) air temperatures are found to be 28° C and 22°C, respectively, at mid day. Under these conditions, the intensity of incident on the vertical conservatory glazing is about 140 W/m². The glazing has a transmissivity of 0.8 to solar radiation, but all surfaces are essentially opaque to long-wave thermal radiation with a corresponding emmisivity & of 0.9. Assuming that the structure is nominally in thermal equilibrium, estimate: (a) The steady-state heat flux through the structure (b) The overall heat transfer coefficient of the structure, defined as U =q/T₁-T, (c) The average temperature in the sun space T= 22°C H STONE WALL SUN SPACE a) Zone I - Exterior glazing surface • Solar Radiation GLAZING L For this project, the system is separated into four zones, with each zone subjected set of analyses. • Convection • Thermal Radiation T₁₂=28°C Heat correlating equation: The wind speed Uoo for a calm day is about 1 corresponding average convective heat transfer coefficient can be estimate- h = 5.8+4.1U