The cylinder is displaced 0.16 m downward from its equilibrium position and is released at time t = 0. Determine the dis
Posted: Tue Jul 05, 2022 10:11 am
The cylinder is displaced 0.16 m downward from its equilibrium position and is released at time t = 0. Determine the displacement y and the velocity v when t = 3.7 s. The displacement and velocity are positive if downward, negative if upward. What is the magnitude of the maximum acceleration? Equilibrium position Answers: When t = 3.7 s: When t = 3.7 s: k = 134 N/m m = 3.2 kg y= V= The maximum acceleration: amax i 3 m/s m/s²