Matrix has 3 eigenvalues, one of which is λ=−1. If the vector is an eigenvector associated with the LARGEST of the eigen
Posted: Tue Jul 05, 2022 10:08 am
Matrix
has 3 eigenvalues, one of which is λ=−1. If the vector
is an eigenvector associated with the LARGEST of the eigenvalues of A, then α+β+γ is equal to
La matriz 5 6 -7 -2 Y tiene 3 valores propios, uno de los cuales es A = -1. Si el vector A = 12 = (8) 1 -6 -10 9 -14 9 5 es un vector propio asociado al MAYOR de los valores propios de A, entonces a + 3+ y es igual a
has 3 eigenvalues, one of which is λ=−1. If the vector
is an eigenvector associated with the LARGEST of the eigenvalues of A, then α+β+γ is equal to
- 1 (47.15 KiB) Viewed 13 times