Find the equation of the line tangent to the function at the given point. Your answer should be in slope-intercept form.
Posted: Tue Jul 05, 2022 10:08 am
Find the equation of the line tangent to the function at the given point. Your answer should be in slope-intercept form. y=x²-6x+3 at (2,-5) 0000 y=-2x-1 y = -6x +3 y=-12x-6 y=-10x-1