Find the equation of the line tangent to the function at the given point. Your answer should be in slope-intercept form.
Posted: Tue Jul 05, 2022 10:07 am
Find the equation of the line tangent to the function at the given point. Your answer should be in slope-intercept form. y=2x²+ + 12x +20 at (-2,4) y = 8x + 18 000 y = 16x + 18 y = 4x+12 y=28x-12