Differentiate the function below with respect to x. y = (4x³ + 5)³(3x³ + 5) dx = 3(4x³ + 5)² · 20x²¹ +9x² = 3x²(20x²(4x
Posted: Tue Jul 05, 2022 10:07 am
Differentiate the function below with respect to x. y = (4x³ + 5)³(3x³ + 5) dx = 3(4x³ + 5)² · 20x²¹ +9x² = 3x²(20x²(4x + 5)²+3) dy = 3(4x + 5)² 20x4.9x² + 3(4x5 + 5)².20x¹.9x² = dx = 1080x (4x + 5)² dy - (4x³ + 5)³.9x² + (3x³ + 5)-3(4x + 5)² - 20x* = dx = 3x²(4x + 5)²(72x³ + 15 + 100x²) dy = (4x5 +5)³.9x² dx