Find Entropy(S) as a function of U , V , N using Internal Energy(U), which is a function of T , N . Please solve it as b
Posted: Sun Apr 10, 2022 6:32 pm
Find Entropy(S) as a function of U , V , N using Internal
Energy(U), which is a function of T , N .
Please solve it as below.
1/2 v [ = 108. ) 2 81h?e? P u(T,P)= 3 kpT loge 3me (kgT)3 F(T, V,N) = 3N kgT loge {(łwp)/(kBT)} (wn = (41e’n/m.)1/2, n=N/ V) B = те
houp I KBT Helmholtz free energy F(T.V, N) = 3NKT loge ( = 3N207 [1941948-roget] from naws of thermodynamics, dF = du - Tds - Sot = Tds -Pdv +UdN-Tds SdT where = SdT-pdv tudN vis internar energy, T is temperature, s is entropy M is Chemical Potential, Nis no. of molecules, P is Pressure, Volume. S = em OF LIT NN --), - OF av NT i Entropy s = ә IT 3 NKAT hwe KB 3 ( tiwe 3 NKB +3 KBT [3NX07 (10ge ( hu ) - 10827)] - [ anketoget at +30*37 (0-7)] 57 • 5*** (?- ngerton)) 3NXo [-loge (Hot) - Toge we] SN xe [- Toge (A) - 1 uge fame ) ] 1 as 1- v .41e²n AS Wp = ме and n = N Intermal energy U = F+TS = 3NXBT loge (Hot (noge ) + 3N107/9-1age [using 9 and ① - 3 NKT
Pressure aF dv NT hwp dv KBT ә dv 3NKBT XBT 2 dv ħ КөT 1+ loge/49e²N 2 me v AS Wp = 4 ne²n me 2 -CF) wt - ( 3 NKBT loge - 39 Kothage (Hot) +3NKT - + 3N KBT loge (WP) Floge (we) - [Kotroge (intet + 3N Kot lage ] CAS N =-( 3nxet vage (Hot) + Sveikatinge [ I (SAWST)* NKET & Enthalpy 3NK&T + ŽNKOT анкет Ams] Entropy S(T»x, N) = 9NK [-dage leather - trage Content) [loge (+ or ) loge Internal energy u(TN) and n = V 3NKBT 141eN 2 me 3 NKBT roge KBT rogel - 3N KOT logelv) ] 2 z 3 2 PV = H = U+PV 2 140en mev " s = 3NKB KBT - 3N KBT Enthalpy H (TN) = 3 NKBT
Energy(U), which is a function of T , N .
Please solve it as below.
1/2 v [ = 108. ) 2 81h?e? P u(T,P)= 3 kpT loge 3me (kgT)3 F(T, V,N) = 3N kgT loge {(łwp)/(kBT)} (wn = (41e’n/m.)1/2, n=N/ V) B = те
houp I KBT Helmholtz free energy F(T.V, N) = 3NKT loge ( = 3N207 [1941948-roget] from naws of thermodynamics, dF = du - Tds - Sot = Tds -Pdv +UdN-Tds SdT where = SdT-pdv tudN vis internar energy, T is temperature, s is entropy M is Chemical Potential, Nis no. of molecules, P is Pressure, Volume. S = em OF LIT NN --), - OF av NT i Entropy s = ә IT 3 NKAT hwe KB 3 ( tiwe 3 NKB +3 KBT [3NX07 (10ge ( hu ) - 10827)] - [ anketoget at +30*37 (0-7)] 57 • 5*** (?- ngerton)) 3NXo [-loge (Hot) - Toge we] SN xe [- Toge (A) - 1 uge fame ) ] 1 as 1- v .41e²n AS Wp = ме and n = N Intermal energy U = F+TS = 3NXBT loge (Hot (noge ) + 3N107/9-1age [using 9 and ① - 3 NKT
Pressure aF dv NT hwp dv KBT ә dv 3NKBT XBT 2 dv ħ КөT 1+ loge/49e²N 2 me v AS Wp = 4 ne²n me 2 -CF) wt - ( 3 NKBT loge - 39 Kothage (Hot) +3NKT - + 3N KBT loge (WP) Floge (we) - [Kotroge (intet + 3N Kot lage ] CAS N =-( 3nxet vage (Hot) + Sveikatinge [ I (SAWST)* NKET & Enthalpy 3NK&T + ŽNKOT анкет Ams] Entropy S(T»x, N) = 9NK [-dage leather - trage Content) [loge (+ or ) loge Internal energy u(TN) and n = V 3NKBT 141eN 2 me 3 NKBT roge KBT rogel - 3N KOT logelv) ] 2 z 3 2 PV = H = U+PV 2 140en mev " s = 3NKB KBT - 3N KBT Enthalpy H (TN) = 3 NKBT