السؤال الرابع: بين أن الاقتران y(t) = exp هو حل للمعادلة التفاضلية التاليه (p(x) = (x + بالاشتقاق والتعويض المباشر في ال

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answerhappygod
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السؤال الرابع: بين أن الاقتران y(t) = exp هو حل للمعادلة التفاضلية التاليه (p(x) = (x + بالاشتقاق والتعويض المباشر في ال

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السؤال الرابع: بين أن الاقتران y(t) = exp هو حل للمعادلة التفاضلية التاليه (p(x) = (x + بالاشتقاق والتعويض المباشر في المعادله [+ſ mest kjeves mora danses to
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