Answer Happy • 3) Show that the limit does not exist. a) lim (x.y)→(0,0) b) lim (x,y)→(0,0) ху 3x² + y² a) f(x, y) = x³ v 2x6 + y² 4) D

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Answer Happy • 3) Show that the limit does not exist. a) lim (x.y)→(0,0) b) lim (x,y)→(0,0) ху 3x² + y² a) f(x, y) = x³ v 2x6 + y² 4) D

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3) Show that the limit does not exist. a) lim (x.y)→(0,0) b) lim (x,y)→(0,0) ху 3x² + y² a) f(x, y) = x³ v 2x6 + y² 4) D

Posted: Tue Jul 05, 2022 10:07 am

by answerhappygod

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3) Show that the limit does not exist. a) lim (x.y)→(0,0) b) lim (x,y)→(0,0) ху 3x² + y² a) f(x, y) = x³ v 2x6 + y² 4) Determine where the function is continuous. x²y 16 – x² - y² ху , b) ƒ(x, y) = { x² + xy + y² ¹ (x, y) # (0,0) [0, (x, y) = (0,0)