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Problem 1 (20 points For the parts of the below question, fill in the empty boxes with your answer (YOUR ANSWER MUST BE ONLY A NUMBER: DO NOT WRITE UNITS; DO NOT WRITE LETTERS) A light wave in air strikes the surface of a piece of material of index 1.529 at at an angle 0,= 33, as shown in the figure. Air ! Material a) 3 points. The sine of the transmission angle is given by: sin(33) #16x9 sin(33) 1.529 1.529 sin(33) b) (2 points Calculate in degrees. 0 = 20 c) IS points] The light wave is now incident perpendicularly on a different material (8. = 33) having an index of 1.724, as shown in the figure below. ei Air Different Material 10 tnew Consider the new angle of transmission = 24. The amplitude transmission coefficient t is given by 2-cos(24) cos(1.724) +1.724 Cos(33) 2-cos(33) COS(33) +1.724 06 (24) 2-cos(1.724) COS(24) +1.724 COS(33) d) 3 points Calculatet t = ) 12 pointsAssume that t=0.4633 and that the electric field amplitude perpendicular to the plane af incidence is Ex=21 V/m. Calculate the transmitted electric field amplitude E. Ex=1 V/m e) Spaints] Consider that the electric field amplitude is now parallel to the plane of incidence (0,= 33 and 0 = 24). Calculate the amplitude transmission coefficient t. t=1