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4. [-/2 Points] DETAILS Explain what it means to say that SCALCET9 2.2.002. lim f(x) = X→ 2- Need Help? = 1 and As x approaches f(x) approaches 7, but f(2): = 1. As x approaches 2 from the right, f(x) approaches 1. As x approaches 2 from the left, f(x) approaches 7. As x approaches 2 from the left, f(x) approaches 1. As x approaches 2 from the right, f(x) approaches 7. As x approaches f(x) approaches 1, but f(2) = 7. In this situation is it possible that_lim_ f(x) exists? Explain. X→ 2 Read It lim f(x) = 7. X→2+ Yes, f(x) could have a hole at (2, 1) and be defined such that f(2) = 7. Yes, f(x) could have a hole at (2, 7) and be defined such that f(2) = 1. Yes, if f(x) has a vertical asymptote at x = 2, it can be defined such that lim__ f(x) = 1, X→2- No, lim f(x) cannot exist if lim_f(x) = X→ 2 X→2- lim f(x). X→2+ MY NOTES lim f(x) = 7, and lim f(x) exists. X→2+ X→2 ASK YOUR TEACHER PRACTICE ANOTHER