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3. [-/2 Points] DETAILS SCALCET9 2.2.001. Explain the meaning of the following equation. lim f(x) = 7 O The values of f(x) can be made as close to 3 as we like by taking x sufficiently close to 7. If Ix₁ - 31 < x₂-31, then |(x₁) - 7|≤ f(x₂) - 71. The values of f(x) can be made as close to 7 as we like by taking x sufficiently close to 3. Of(x) = 7 for all values of x. If Ix₁ - 31 < x₂-31, then f(x₁) − 7| < |F(x₂) - 7|. Is it possible for this statement to be true and yet f(3) = 6? Explain. O Yes, the graph could have a hole at (3, 7) and be defined such that f(3) = 6. O Yes, the graph could have a vertical asymptote at x = 3 and be defined such that f(3) = 6. O No, if f(3) = 6, then lim f(x) = 6. No, if lim f(x) = 7, then f(3) = 7. x 3 Need Help? Read It Watch It MY NOTES ASK YOUR TEACHER PRACTICE ANOTI