Answer Happy

I'm trying to calculate the % difference of a Uniform
Circular Motion Lab, but my answers are too high, not sure if this
is correct.
We were asked to:
Calculate the absolute difference between the experimentally
determined force (as obtained by the stopper’s
information) and the expected force (as
obtained by the hanging mass – recall the force on the hanging mass
should equal the force on the stopper). Put
these differences in your data table. Since both measurements
are experimental values that we want to compare, use the percent
difference analysis (as opposed to the percent error). Do a
percent difference for each value:
%Difference = [(measurement 1 – measurement 2)/
AVERAGE(measurement1&2)]*100
Thanks in advance!
% Difference = X 100 (measurement 1 – measurement 2) AVERAGE 10T1s) Badius (m) T (s) (mis) Fc (N) 0.10 2.485 0.2485 2.528 1.917 0.20 3:483 0.3483 3.609 1.954 0.30 4.235 0.4235 4.4510 1-981 Mass of Stopper: 309 Hanging Mass 2009 0.03 kg 0.2 kg T-W = mu? (0-20kg)( 2 528 mls 34 1.278 0.10m 12.78 N 0.10 m % 10-863 x 100 = 12.78 N -1917N)x100 12-78N +1-917N) 147.827 7.3485 2 T-W = (0-20kg) ( 3.609)² 2.605 13.02N 0.20m 0.20m ( 13.02 – 1954) x 100 11.066 x 100 147.80 1 7.487 7.487 T-W=(0-20kg)(4.4510) 3.962 13.21 N 0.30m 0.30 m % = (13.21-1-981) x 100 7.5955 = !1.229 x 100 147.84 1. 7.5955