Answer Happy

You may need to use the appropriate technology to answer this question. Three different methods for assembling a product were proposed by an industrial engineer. To investigate the number of units assembled correctly with each method, 36 employees were randomly selected and randomly assigned to the three proposed methods in such a way that each method was used by 12 workers. The number of units assembled correctly was recorded, and the analysis of variance procedure was applied to the resulting data set. The following results were obtained: SST = 12,250; SSTR = 4,510. (a) Set up the ANOVA table for this problem. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.) Source of Variation Treatments Error Total Sum of Squares Degrees of Freedom O Ho: Not all the population means are equal. H₂: M₁ = H₂ = 13 оно (1 =H2=3 на: М1 #М2 + Из Mean Square (b) Use a = 0.05 to test for any significant difference in the means for the three assembly methods. State the null and alternative hypotheses. ⒸH₂= μ₁₂ = μ₁₂ = 13 Ha: Not all the population means are equal. O Ho: At least two of the population means are equal. H₂: At least two of the population means are different. O Ho: M₁ M₂ # H¹3 H₂: M₁ = H₂ = 13 Find the value of the test statistic. (Round your answer to two decimal places.) F Find the p-value. (Round your answer to four decimal places.) p-value = p-value State your conclusion. O Do not reject Ho. There is sufficient evidence to conclude that the means of the three assembly methods are not equal. O Reject Ho. There is sufficient evidence to conclude that the means of the three assembly methods are not equal. O Reject Ho. There is not sufficient evidence to conclude that the means of the three assembly methods are not equal. O Do not reject Ho. There is not sufficient evidence to conclude that the means of the three assembly methods are not equal.