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C₁1H23 C₁1 H23 1. m-CPBA, CH₂Cl₂, 73% 2. t-BuMe,SICI, imidazole, DMF, 83% OH 4 OH 6 1. Na/C6H₁31 2. (+)-(IPC)₂BH then H₂

Posted: Tue Jul 05, 2022 9:16 am
by answerhappygod
C 1h23 C 1 H23 1 M Cpba Ch Cl 73 2 T Bume Sici Imidazole Dmf 83 Oh 4 Oh 6 1 Na C6h 31 2 Ipc Bh Then H 1
C 1h23 C 1 H23 1 M Cpba Ch Cl 73 2 T Bume Sici Imidazole Dmf 83 Oh 4 Oh 6 1 Na C6h 31 2 Ipc Bh Then H 1 (123.96 KiB) Viewed 14 times
1. What is the function of the 3rd reagent upon the formation ofcompound 7?
2. Why the reagent is chosen instead of others?
3. What product will be formed if the other similar?
Thank you.....
C₁1H23 C₁1 H23 1. m-CPBA, CH₂Cl₂, 73% 2. t-BuMe,SICI, imidazole, DMF, 83% OH 4 OH 6 1. Na/C6H₁31 2. (+)-(IPC)₂BH then H₂O₂ 65% C₁1H23 C6H₁3 OSiMe₂t-Bu C6H₁3 1. HF, CH₂CN, 94% 2. NaOH, EtOH/H₂O 50 °C, 4 h, 99% 9 1 LOH C6H₁3 C₂H13 PhCO₂H, DEAD, PPh 3, 72% 2.5% KOH/MeOH, 50 °C, 3h, 62% 1. (COCI)₂, DMSO then Et₂N, 89% 2. HF, 71% C₁1H23 1. 8 3 -C6H₁3 OSiMe₂t-Bu 1. t-BuMe,SICI, imidazole, DMF, 90% 2. KOH, BnBr, dioxane, 81% 3. Cl₂CCNH(OBn), CF₂SO3H, 71% C₁₁ ₂23 CO₂H C6H₁3 www 1. N-Cbz-Leu, DCC, 85% 2. H₂, 10% Pd/C, THF 3. ACOCHO, THF, 72% 5 (C₁1H23)2 Cu(CN)Li₂ Et₂O, -20 °C, 2 h, 68% (regioselective) C6H₁3 OSiMe₂t-Bu C11H₂3 7 C11H23 2 m-CPBA CH₂Cl₂, 73% QBn QSiMe t-Bu simene CO₂Bn NH CHO 1. PhSO₂Cl, pyr 69% 2. H₂, 10% Pd/C, THF, 95% 10 (regioselective) C6H13 OH C₂H13 C6H13